what can you do with just binary or ternary raster operations ?

What soft of bit twiddling can and can't you do using binary or ternary raster arithmetic with blitting functions. Some more examples of bit twiddling: avoiding branches in chess programming, hacker's delight

http://www.stackoverflow.com/questions/3649194/

Posted: September 6, 2010 at 5:23 AM by: Naveen

arithmetic in a Makefile

arithmetic in a Makefile Is it possible to perform some operations on variables in a Makefile. For instance, defining JPI=4 JPJ=2 Is it possible to define in the same Makefile a variable JPIJ equal to the expanded value of $(JPI)*$(JPJ) ? If you're using GNU make and have bc installed on your system, you can use something like this: JPI=4 JPJ=2 FOO=$(shell echo $(JPI)\*$(JPJ) | bc) all: echo $(FOO) It's clumsy (or brilliant, depending on your perspective), but you can do arithmetic directly in GNU make. See Learning GNU Make Functions with Arithmetic. Be aware though that this method doesn't scale well. It will work wonderfully for small numbers as you have shown in your question, but it doesn't do well when you're working with numbers with a large magnitude (greater than 10,000,000

arithmetic in a Makefile Is it possible to perform some operations on variables in a Makefile. For instance, defining JPI=4 JPJ=2 Is it possible to define in the same Makefile a variable JPIJ equal to the expanded value of $(JPI)*$(JPJ) ? If you're using GNU make and have bc installed on your system, you can use something like this: JPI=4 JPJ=2 FOO=$(shell echo $(JPI)\*$(JPJ) | bc) all: echo $(FOO) It's clumsy (or brilliant, depending on your perspective), but you can do arithmetic directly in GNU make. See Learning GNU Make Functions with Arithmetic. Be aware though that this method doesn't scale well. It will work wonderfully for small numbers as you have shown in your question, but it doesn't do well when you're working with numbers with a large magnitude (greater than 10,000,000

Arithmetic + and Bitwise OR

Arithmetic + and Bitwise OR Is there any difference between Arithmetic + and bitwise OR. In what way this is differing. uint a = 10; uint b = 20; uint arithmeticresult = a + b; uint bitwiseOR = a | b; Both the results are 30. Edit : Small changes to hide my stupidity. Counterexample: 2 + 2...) (1+1=2) 00000010 OR 00000010 Result 00000010 VS 00000010 + 00000010 Result 00000100 Bitwise OR goes through every bit of two digits and applies the following truth table: A B | A|B 0 0 | 0 0 1 | 1 1 0 | 1 1 1 | 1 Meanwhile the arithmetic + operator actually..., or the bit is set in B but not A. In that case the arithmetic + and the bit-wise or would produce the same result... as would the bitwise xor for that matter. Try setting a = 230 and b = 120. And you'll observer the difference in results. The reason is very simple. In the arithmentic addition

Arithmetic + and Bitwise OR Is there any difference between Arithmetic + and bitwise OR. In what way this is differing. uint a = 10; uint b = 20; uint arithmeticresult = a + b; uint bitwiseOR = a | b; Both the results are 30. Edit : Small changes to hide my stupidity. Counterexample: 2 + 2...) (1+1=2) 00000010 OR 00000010 Result 00000010 VS 00000010 + 00000010 Result 00000100 Bitwise OR goes through every bit of two digits and applies the following truth table: A B | A|B 0 0 | 0 0 1 | 1 1 0 | 1 1 1 | 1 Meanwhile the arithmetic + operator actually..., or the bit is set in B but not A. In that case the arithmetic + and the bit-wise or would produce the same result... as would the bitwise xor for that matter. Try setting a = 230 and b = 120. And you'll observer the difference in results. The reason is very simple. In the arithmentic addition

Modular arithmetic

Modular arithmetic I'm new to cryptography and modular arithmetic. So, I'm sure it's a silly question, but I can't help it. How do I calculate a from pow(a,q) = 1 (mod p), where p and q are known? I don't get the "1 (mod p)" part, it equals to 1, doesn't it? If so, than... from a programming perspective, another way of saying it is that pow(a,q)%p=1, where "%" is the "remainder" operator as implemented in several languages (assuming that p>1). You should read the Wikipedia article on Modular arithmetic, or any elementary number theory book (or even a cryptography book, since it is likely to introduce modular arithmetic). To answer your other question: there is no general formula for finding such an a (to the best of my knowledge) in general. Assuming that p is prime, and using Fermat's little theorem to reduce q modulo p-1, and assuming that q divides p-1

Modular arithmetic I'm new to cryptography and modular arithmetic. So, I'm sure it's a silly question, but I can't help it. How do I calculate a from pow(a,q) = 1 (mod p), where p and q are known? I don't get the "1 (mod p)" part, it equals to 1, doesn't it? If so, than... from a programming perspective, another way of saying it is that pow(a,q)%p=1, where "%" is the "remainder" operator as implemented in several languages (assuming that p>1). You should read the Wikipedia article on Modular arithmetic, or any elementary number theory book (or even a cryptography book, since it is likely to introduce modular arithmetic). To answer your other question: there is no general formula for finding such an a (to the best of my knowledge) in general. Assuming that p is prime, and using Fermat's little theorem to reduce q modulo p-1, and assuming that q divides p-1

Pointer Arithmetic

Pointer Arithmetic Does anyone have any good articles or explanations (blogs, examples) for pointer arithmetic? Figure the audience is a bunch of Java programmers learning C and C++. First, the binky video may help. It's a nice video about pointers. For arithmetic, here is an example: int * pa... the generic typedef ptrdiff_t. Here is where I learned pointers: http://www.cplusplus.com/doc/tutorial/pointers.html Once you understand pointers, pointer arithmetic is easy. The only difference between it and regular arithmetic is that the number you are adding to the pointer will be multiplied by the size of the type that the pointer is pointing to. For example, if you have a pointer to an int and an int's size is 4 bytes, (pointer_to_int + 4) will evaluate to a memory address 16 bytes (4 ints) ahead. So when you write (a_pointer + a_number) in pointer arithmetic, what's really

Pointer Arithmetic Does anyone have any good articles or explanations (blogs, examples) for pointer arithmetic? Figure the audience is a bunch of Java programmers learning C and C++. First, the binky video may help. It's a nice video about pointers. For arithmetic, here is an example: int * pa... the generic typedef ptrdiff_t. Here is where I learned pointers: http://www.cplusplus.com/doc/tutorial/pointers.html Once you understand pointers, pointer arithmetic is easy. The only difference between it and regular arithmetic is that the number you are adding to the pointer will be multiplied by the size of the type that the pointer is pointing to. For example, if you have a pointer to an int and an int's size is 4 bytes, (pointer_to_int + 4) will evaluate to a memory address 16 bytes (4 ints) ahead. So when you write (a_pointer + a_number) in pointer arithmetic, what's really

Arithmetic in ruby

Arithmetic in ruby Why this code 7.30 - 7.20 in ruby returns 0.0999999999999996, not 0.10? But if i'll write 7.30 - 7.16, for example, everything will be ok, i'll get 0.14. What the problem, and how can i solve it? That is a common error from how float point numbers are represented in memory...-in-floating-point-numbers What Every Computer Scientist Should Know About Floating-Point Arithmetic The problem is that some numbers we can easily write in decimal don't have an exact representation in the particular floating point format implemented by current hardware. A casual way of stating... of people don't even realize that JS does everything in floating point. Use fixed point arithmetic. Ruby actually makes this really easy; it's one of the only languages that seamlessly shifts to Class Bignum from Fixnum as numbers get bigger. Use a class that is designed to solve this problem, like

Arithmetic in ruby Why this code 7.30 - 7.20 in ruby returns 0.0999999999999996, not 0.10? But if i'll write 7.30 - 7.16, for example, everything will be ok, i'll get 0.14. What the problem, and how can i solve it? That is a common error from how float point numbers are represented in memory...-in-floating-point-numbers What Every Computer Scientist Should Know About Floating-Point Arithmetic The problem is that some numbers we can easily write in decimal don't have an exact representation in the particular floating point format implemented by current hardware. A casual way of stating... of people don't even realize that JS does everything in floating point. Use fixed point arithmetic. Ruby actually makes this really easy; it's one of the only languages that seamlessly shifts to Class Bignum from Fixnum as numbers get bigger. Use a class that is designed to solve this problem, like

Pointer arithmetic.

Pointer arithmetic. Having code: int** a = new int*[2]; a[0] = new int(1); a[1] = new int(2); cout << "a[0] " << a[0] << '\n'; cout << "a[1] " << a[1] << '\n'; cout << "a[2] " << a[2] << '\n'; cout << "a[0] + 1 " << a[0] + 1 << '\n';//WHY THIS ISN'T == a[1] ? cout << "*(a + 1): " << *(a + 1) << '\n'; //WHY THIS IS == a[1] ? cout << "a[0] - a[1] " << static_cast<int>(a[0] - a[1])<< '\n';//WHY THIS IS == 16 not 4? cout << sizeof(int**); Questions are included right next to relevant lines in code. a[0] and a[1] are contiguous, and they are both pointers, but they do not point to contiguous areas of memory. That's because the memory pointers returned by the new operator are effectively unpredictable. In other words, there is no guarantee (in fact quite opposite

Pointer arithmetic. Having code: int** a = new int*[2]; a[0] = new int(1); a[1] = new int(2); cout << "a[0] " << a[0] << '\n'; cout << "a[1] " << a[1] << '\n'; cout << "a[2] " << a[2] << '\n'; cout << "a[0] + 1 " << a[0] + 1 << '\n';//WHY THIS ISN'T == a[1] ? cout << "*(a + 1): " << *(a + 1) << '\n'; //WHY THIS IS == a[1] ? cout << "a[0] - a[1] " << static_cast<int>(a[0] - a[1])<< '\n';//WHY THIS IS == 16 not 4? cout << sizeof(int**); Questions are included right next to relevant lines in code. a[0] and a[1] are contiguous, and they are both pointers, but they do not point to contiguous areas of memory. That's because the memory pointers returned by the new operator are effectively unpredictable. In other words, there is no guarantee (in fact quite opposite

bash: $[] vs. $(())

bash: $[] vs. $(()) I have just stumbled upon the bash syntax: foo=42 bar=$[foo+1] # evaluates an arithmetic expression When I Googled for this, I found http://tldp.org/LDP/Bash-Beginners-Guide/html/sect_03_04.html#sect_03_04_05: 3.4.6. Arithmetic expansion Arithmetic expansion allows the evaluation of an arithmetic expression and the substitution of the result. The format for arithmetic expansion is: $(( EXPRESSION )) ... Wherever possible, Bash users should try to use the syntax with square brackets: $[ EXPRESSION ] However, this will only calculate the result of EXPRESSION, and do no tests... In my bash man page I can only find the $(( EXPRESSION )) form such as: foo=42 bar=$((foo+1)) # evaluates an arithmetic expression So what tests are not performed with $[...] that do with $((...)), or is the $[...] just a legacy version

bash: $[] vs. $(()) I have just stumbled upon the bash syntax: foo=42 bar=$[foo+1] # evaluates an arithmetic expression When I Googled for this, I found http://tldp.org/LDP/Bash-Beginners-Guide/html/sect_03_04.html#sect_03_04_05: 3.4.6. Arithmetic expansion Arithmetic expansion allows the evaluation of an arithmetic expression and the substitution of the result. The format for arithmetic expansion is: $(( EXPRESSION )) ... Wherever possible, Bash users should try to use the syntax with square brackets: $[ EXPRESSION ] However, this will only calculate the result of EXPRESSION, and do no tests... In my bash man page I can only find the $(( EXPRESSION )) form such as: foo=42 bar=$((foo+1)) # evaluates an arithmetic expression So what tests are not performed with $[...] that do with $((...)), or is the $[...] just a legacy version

Question on Pointer Arithmetic

Question on Pointer Arithmetic Heyy Everybody! I am trying to create a memory management system, so that a user can call myMalloc, a method I created. I have a linked list keeping track of my free memory. My problem is when I am attempting to find the end of a free bit in my linked list. I am... of that segment. However, I keep getting the warning: "pointer of type 'void*' used in arithmetic" Is there a better way of doing this? Thanks! Pointer arithmetic uses the size of the underlying type. If int is 4 bytes: int *p = some_address; p++; will increment p by 4 bytes. void can't be used in pointer arithmetic because void has no size associated with. If you want to do byte-sized arithmetic on void pointers, you need to cast the pointers to a byte-sized type. int *tailEnd = ( int* ) ( previousPlace->head_ptr + ((previousPlace->size+1)*(sizeof(int

Question on Pointer Arithmetic Heyy Everybody! I am trying to create a memory management system, so that a user can call myMalloc, a method I created. I have a linked list keeping track of my free memory. My problem is when I am attempting to find the end of a free bit in my linked list. I am... of that segment. However, I keep getting the warning: "pointer of type 'void*' used in arithmetic" Is there a better way of doing this? Thanks! Pointer arithmetic uses the size of the underlying type. If int is 4 bytes: int *p = some_address; p++; will increment p by 4 bytes. void can't be used in pointer arithmetic because void has no size associated with. If you want to do byte-sized arithmetic on void pointers, you need to cast the pointers to a byte-sized type. int *tailEnd = ( int* ) ( previousPlace->head_ptr + ((previousPlace->size+1)*(sizeof(int

Fixed-point arithmetic

Fixed-point arithmetic Does anyone know of a library to do fixed point arithmetic in Python? Or, does anyone has sample code? If you are interested in doing fixed point arithmetic, the Python Standard Library has a decimal module that can do it. Actually, it has a more flexible floating point ability than the built-in too. By flexible I mean that it: Has "signals" for various exceptional conditions (these can be set to do a variety of things on signaling) Has positive and negative infinities, as well as NaN (not a number) Can differentiate between positive and negative 0 Allows you to set different rounding schemes. Allows you to set your own min and max values. All in all, it is handy for a million household uses

Fixed-point arithmetic Does anyone know of a library to do fixed point arithmetic in Python? Or, does anyone has sample code? If you are interested in doing fixed point arithmetic, the Python Standard Library has a decimal module that can do it. Actually, it has a more flexible floating point ability than the built-in too. By flexible I mean that it: Has "signals" for various exceptional conditions (these can be set to do a variety of things on signaling) Has positive and negative infinities, as well as NaN (not a number) Can differentiate between positive and negative 0 Allows you to set different rounding schemes. Allows you to set your own min and max values. All in all, it is handy for a million household uses

Java floating point arithmetic

Java floating point arithmetic Hello I need to do some floating point arithmetic in java as shown in the code below: public class TestMain { private static Map<Integer, Double> ccc = new HashMap<Integer, Double>() { { put(1, 0.01); put(2, 0.02); put(3, 0.05... of values outputed by the Betfair spinner widget... http://help.betfair.com/contents/itemId/i65767327/index.en.html Floating point arithmetic in Java seems to introduce some unexpected errors. For example, I get 2.180000000000001 instead of 2.18 Anybody know how I can get round this issue. What use are floating point numbers is you can't trust the results of arithmetic performed on them? Thanks Floating-point numbers are imprecise, especially since they work in binary fractions (1/2, 1/4, 1/8, 1/16, 1/32, ...) instead of decimal fractions (1/10, 1/100, 1/1000, ...). Just define what you feel

Java floating point arithmetic Hello I need to do some floating point arithmetic in java as shown in the code below: public class TestMain { private static Map<Integer, Double> ccc = new HashMap<Integer, Double>() { { put(1, 0.01); put(2, 0.02); put(3, 0.05... of values outputed by the Betfair spinner widget... http://help.betfair.com/contents/itemId/i65767327/index.en.html Floating point arithmetic in Java seems to introduce some unexpected errors. For example, I get 2.180000000000001 instead of 2.18 Anybody know how I can get round this issue. What use are floating point numbers is you can't trust the results of arithmetic performed on them? Thanks Floating-point numbers are imprecise, especially since they work in binary fractions (1/2, 1/4, 1/8, 1/16, 1/32, ...) instead of decimal fractions (1/10, 1/100, 1/1000, ...). Just define what you feel

Arithmetic with pointer types/

Arithmetic with pointer types/ Some examples of adding and subtracting similarly typed pointers, using numeric and character pointers please. Using C. Thanks. You can check this to know about pointer arithmetic Here's a practical example which extracts a single character from a C string: char charAt( char *str, size_t idx) { if (idx > strlen (str)) return '\0'; return *(str+idx); } Or another, which swaps an integer in an array with the one immediately before it (with no range checking): void swapInts( int *base, size_t idx) { tmp = *(base+idx); *(base+idx) = *(base+idx-1); *(base+idx-1) = tmp; } In both these cases, *(pointer+offset) is identical to pointer[offfset] but using pointer arithmetic instead of array offsets: *(str+idx) -> str[idx] *(base+idx) -> base[idx] *(base+idx-1] -> base[idx-1] Warning

Arithmetic with pointer types/ Some examples of adding and subtracting similarly typed pointers, using numeric and character pointers please. Using C. Thanks. You can check this to know about pointer arithmetic Here's a practical example which extracts a single character from a C string: char charAt( char *str, size_t idx) { if (idx > strlen (str)) return '\0'; return *(str+idx); } Or another, which swaps an integer in an array with the one immediately before it (with no range checking): void swapInts( int *base, size_t idx) { tmp = *(base+idx); *(base+idx) = *(base+idx-1); *(base+idx-1) = tmp; } In both these cases, *(pointer+offset) is identical to pointer[offfset] but using pointer arithmetic instead of array offsets: *(str+idx) -> str[idx] *(base+idx) -> base[idx] *(base+idx-1] -> base[idx-1] Warning

BASH Arithmetic Expressions

BASH Arithmetic Expressions I had used several ways to do some simple integer arithmetic in BASH (3.2). But I can't figure out the best (preferred) way to do it. result=`expr 1 + 2` result=$(( 1 + 2 )) let "result = 1 + 2" What are the fundamental differences between those expressions? Is there other ways to do the same? Is the use of a tool like bc mandatory for floating point arithmetic? result=`echo "7/354" | bc` I can't say it's "mandatory" but bc is probably your best bet for general purpose arithmetic. For something fancier, you can always pipe through Perl. The downside...} # result: 4 Edit: The $(()) construct is called "arithmetic expansion" and causes the contents to be evaluated as an integer expression. It's a syntax element of the shell. If a variable is declared as an integer you don't need to use either form of double parentheses, you can omit the dollar sign

BASH Arithmetic Expressions I had used several ways to do some simple integer arithmetic in BASH (3.2). But I can't figure out the best (preferred) way to do it. result=`expr 1 + 2` result=$(( 1 + 2 )) let "result = 1 + 2" What are the fundamental differences between those expressions? Is there other ways to do the same? Is the use of a tool like bc mandatory for floating point arithmetic? result=`echo "7/354" | bc` I can't say it's "mandatory" but bc is probably your best bet for general purpose arithmetic. For something fancier, you can always pipe through Perl. The downside...} # result: 4 Edit: The $(()) construct is called "arithmetic expansion" and causes the contents to be evaluated as an integer expression. It's a syntax element of the shell. If a variable is declared as an integer you don't need to use either form of double parentheses, you can omit the dollar sign

Date arithmetic in Java

Date arithmetic in Java My program is about generating (producing) a Kurosawa and making the customers produce it. Every time we generate a Kurosawa, we have to print its id, its production date and expiration date, which is 3 months from the production date. My problem is: How can I calculate the date after 3 months? Thank you. I believe that the Java Calendar Library should help you. Use the built-in Java Calendar API. Calendar c = Calendar.getInstance(); c.add(Calendar.MONTH, 3); Refer to the API for exactly how to print out the date, in the format you are looking for. You could also... API. If you need to work with date arithmetic JODA works better, as Calendar likes timestamps

Date arithmetic in Java My program is about generating (producing) a Kurosawa and making the customers produce it. Every time we generate a Kurosawa, we have to print its id, its production date and expiration date, which is 3 months from the production date. My problem is: How can I calculate the date after 3 months? Thank you. I believe that the Java Calendar Library should help you. Use the built-in Java Calendar API. Calendar c = Calendar.getInstance(); c.add(Calendar.MONTH, 3); Refer to the API for exactly how to print out the date, in the format you are looking for. You could also... API. If you need to work with date arithmetic JODA works better, as Calendar likes timestamps

Matrix arithmetic in PHP again

Matrix arithmetic in PHP again Hi, I recently asked a question about matrix libraries in PHP. I went with the suggestion of using the Math_Matrix PEAR library. However, it turns out that this library is out of date (meaning I had to change some of the code in the library to make it work with my version of PHP), and it doesn't really do what I need (e.g., it won't let you transpose a non-square matrix, for some reason). I wonder if anyone has any experience of working with matrices in PHP, and if they can recommend a library that they consider to be workable. Thanks, Ben

Matrix arithmetic in PHP again Hi, I recently asked a question about matrix libraries in PHP. I went with the suggestion of using the Math_Matrix PEAR library. However, it turns out that this library is out of date (meaning I had to change some of the code in the library to make it work with my version of PHP), and it doesn't really do what I need (e.g., it won't let you transpose a non-square matrix, for some reason). I wonder if anyone has any experience of working with matrices in PHP, and if they can recommend a library that they consider to be workable. Thanks, Ben

Overloading Arithmetic Operators

Overloading Arithmetic Operators The assignment operator can be declared as T& operator= (const t&); in a class, but the arithmetic operators cannot be defined that way. It has to be friend function. I don't understand why? Can you please explain ? They ideally should be globals and not necessarily friends, so that you can write: yourtype v = 1; yourtype w = 1 + v; Since, 1 is not an object of yourtype, if the operator+ were a member it would throw a fit. However, making it global makes it convert the 1 to yourtype and then perform the operation. Making it a friend helps to extract and manipulate the members of yourtype as required -- though not required. As an example: You can implement the member function operator+= and use it in the implementation of the operator+. I think that C++ FAQ Lite will give you a definitive answer. It is not mandatory that arithmetic operators

Overloading Arithmetic Operators The assignment operator can be declared as T& operator= (const t&); in a class, but the arithmetic operators cannot be defined that way. It has to be friend function. I don't understand why? Can you please explain ? They ideally should be globals and not necessarily friends, so that you can write: yourtype v = 1; yourtype w = 1 + v; Since, 1 is not an object of yourtype, if the operator+ were a member it would throw a fit. However, making it global makes it convert the 1 to yourtype and then perform the operation. Making it a friend helps to extract and manipulate the members of yourtype as required -- though not required. As an example: You can implement the member function operator+= and use it in the implementation of the operator+. I think that C++ FAQ Lite will give you a definitive answer. It is not mandatory that arithmetic operators

2 bit Adding Machine in Minecr

I just made a 4-bit adder! Here's the video: www.youtube.com . It's still uploading as I write this

I just made a 4-bit adder! Here's the video: www.youtube.com . It's still uploading as I write this but it'll be done soon. I've been playing a game called "minecraft" a little bit recently, and I was inspired by the 16-bit ALU (arithmetic logic unit) video to make a little 2 bit adding machine. It's really simple and works as far as I can tell, with only one problem: if one or both of the inputs are 00, then my machine breaks. (Right now it says that 00 + 00 = 110, which is obviously not true). It's also impossible to fill up all three bits in the output, since the maximum value that two bits can hold is 3 (2^2 - 1) and the maximum value of three bits is 7 (2^3 - 1). I'm hoping that I can expand this concept into a four-bit machine sometime, but that takes time and patience, and I tend to be short on both when it comes to long projects. EDIT 11/6/2010: The schematic for this is here: img708.imageshack.us . For more on logic gates, this article is great: en.wikipedia.org EDIT 2: This is the schematic for a correctly working adder generalized to n bits: img574.imageshack.us . The section labeled 1 is a "half adder", which doesn't utilize a C (carry) in value. All other bits require a "full adder" (label 2) which has a carry in and carry out. The gates in label 2 can be repeated as many times as desired for an bit adder; for example, an n bit adder would have 1 half adder and n - 1 full adders.

Roland D-50: thesynthfreq's or

Hi! this a video of the patches that I have programmed for my Roland D-50. Since replacing the very

Hi! this a video of the patches that I have programmed for my Roland D-50. Since replacing the very old lithium battery, all the patches were erased and I am re-typing them in one at a time. These are the ones that I have replaced so far. I have more patches than whats on here, but I will make another video once I reprogram those other patches back in the D-50. The D-50 is my favorite synth of the late 80s and is a lot of fun to program. It take me about 2 hours to make a good and useful patch. I am just improving the sequences and "songs" that I am playing to show each sound. D-50 uses Linear Arithmetic Synthesis. Got to have those waveforms! :)

Game Programming Tutorial 4 in

We implement a program in which we can send a character around the screen by clicking on different p

We implement a program in which we can send a character around the screen by clicking on different positions. In process of doing so, we will learn about how to use vectors and how to do simple arithmetic with them. I'll also show you some drawing tricks. All supplementary material can be found on karpathy.ca I messed up a tiny bit in this tutorial in mouseUp() method. The line should be self.target= vec2d(pos) instead of self.target= pos I go into full story in the link if you are interested, but I will also go over this issue in more depth in later videos.

PURE DATA: Lesson 03, Basic Ma

Video tutorials on Pure Data (Pd) with Dr. Rafael Hernandez. In this lesson, doing basic arithmetic

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SPB Brain Evolution 2: intelle

SPB Brain Evolution is an intellectual software game that helps to train the brain and improve memor

SPB Brain Evolution is an intellectual software game that helps to train the brain and improve memory, logic, arithmetic, and puzzle-solving skills. The application is a suit of 12 mobile games, which have to be played in sequence: only good results in a game unlock the next one. Watch this video to sneak a peek on how the game is organized and what benefits it offers to the users. spb.com

Java Tutorial 7 : Switch, Else

Covering more conditional expressions - the Switch statement, else if statements and a new arithmeti

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SPB Brain Evolution: intellect

SPB Brain Evolution is the best-selling mobile game in 2008 world-wide that helps to train the brain

SPB Brain Evolution is the best-selling mobile game in 2008 world-wide that helps to train the brain and improve memory, logic, arithmetic, and puzzle-solving skills. The application is a suit of 10 games, which have to be played in sequence: only good results in a game unlock the next one. Watch this video to sneak a peek on how the game is organized and what benefits it offers to the users. itunes.apple.com

Java Video Tutorial 7: Arithme

This is the first part of a two part java video tutorial discussing the usage of arithmetic and unar

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About Computer Processor (CPU)

about Computer Processor (CPU) and Arithmetic Logic Unit (ALU) -- a set of electronic circuits that

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chapter 3 Arithmetic Instructi

This chapters tells about Arithmetic instructions, their use, arithmetic operator, unary operator, s

This chapters tells about Arithmetic instructions, their use, arithmetic operator, unary operator, sizeof, type cast etc. Complete C tutorial contains: running time 18 hours. Introduction, C Basics, Arithmetic Instructions, Decision Making, Loops, Arrays, Functions, Pointers, File I/O and more... contact : geeta@learnbywatch.com

Old School FreeStyle Beat Prod

BEAT I Made In FL Studio 9 Hope U Like It extra tags n shitt: lil wayne mike tyson american dream am

BEAT I Made In FL Studio 9 Hope U Like It extra tags n shitt: lil wayne mike tyson american dream american dream mike tyson lil wayne new lil wayne 2008 carter 3 mrs.officer radio mrs. officer single mrs. officer official music video documentary, lil wayne documentary. dedication 3 drama. dedication 3 mixtape. dedication 3 album. weezy f. 3 Peat Mr. Carter Feat. Jay-Z A Milli Got Money Feat. T-Pain Comfortable Feat. Babyface Dr. Carter Phone Home Tie My Hands Feat. Robin Thicke Mrs. Officer Feat. Bobby Valentino Let The Beat Build Shoot Me Down Feat. D. Smith Lollipop Feat. Static Major La La Feat. Brisco & Busta Rhymes Playing With Fire Feat. Betty Wrigh You Ain't Got Nuthin Feat. Juelz Santana & Fabolous Dontgetit 2pac tupac shakur 50 cent biggi diddy dmx mike tyson wwe Timbaland xzibit nelly eminem slim shady akon mario kanye west Lil Mama featuring Chris Brown T-Pain;Lil T-Pain Shawty Get Loose Rap Music Video Lil Mama g-slide gslide tour bus Lip Gloss hip machinima animation game movies news comedy gta grand theft auto videos funny hop dance rap soulja boy crank that huey kanye ciara 50cent rihanna Lil Mama Lip Gloss hiphop hip hop dance krump rap soulja boy crank that huey kanye fergie ciara 50cent rihanna beyonce Urban Music News Pop Rihanna Lil Mama Jay-Z Ne-Yo Good Girl Gone Bad l mama chris brown tpain t-pain shawty shorty get loose low flo rida with you kiss bet dance michael jackson Ludacris ft Young Jeezy - Grew Up A Screw Up Ludacris ft Young Jeezy - Grew Up

Java Video Tutorial 8: Arithme

This is the second part of a two part java video tutorial discussing the usage of arithmetic and una

This is the second part of a two part java video tutorial discussing the usage of arithmetic and unary operators in java programming. All tutorials use the Eclipse IDE.

Mildot Rangefinding, Laser Ran

At longer ranges, a small rangefinding error can make you miss the target. For a given target size y

At longer ranges, a small rangefinding error can make you miss the target. For a given target size you will have a stretch of ground called the Danger Zone. Inside the Danger Zone most of your shots hit the target. Outside the Danger Zone most of your shots miss the target. Mil dot rangefinding may not be accurate enough, even if your mental arithmetic is super. So do consider using a laser for longer ranges. Inside the Danger Zone most of your shots hit the target. www.gunsim.com

SPB Brain Evolution for Window

SPB Brain Evolution is an intellectual game that helps to train the brain and improve memory, logic,

SPB Brain Evolution is an intellectual game that helps to train the brain and improve memory, logic, arithmetic, and puzzle-solving skills using your touchscreen mobile phone. The application is a suit of 12 games, which have to be played in sequence: only good results in a game unlock the next one. Watch this video to sneak a peek on how the game is organized and what benefits it offers to the mobile users.

SPB Brain Evolution 2: intelle

SPB Brain Evolution is the best-selling mobile game in 2008 world-wide that helps to train the brain

SPB Brain Evolution is the best-selling mobile game in 2008 world-wide that helps to train the brain and improve memory, logic, arithmetic, and puzzle-solving skills. The application is a suit of 10 games, which have to be played in sequence: only good results in a game unlock the next one. Watch this video to sneak a peek on how the game is organized and what benefits it offers to the users. spb.com

Intro to CS 002 - Arithmetic

Arithmetic in scheme. Prefix vs infix notation. From an introduction to computer science online cour

Arithmetic in scheme. Prefix vs infix notation. From an introduction to computer science online course.

MathKnack Genius

Appstore link: itunes.apple.com Game Description Prepare your brain ready to face an exciting Math c

Appstore link: itunes.apple.com Game Description Prepare your brain ready to face an exciting Math challenge! See how fast you can solve simple equations by filling in the missing operators! Improve your speed to achieve Genius status. Play with 2, 3, or 4 terms in the equations, in three different difficulty settings: Student, Graduate, or Genius! Benefits You'll get smarter and be able to solve and understand arithmetic equations faster and more easily! Game Modes - Time Trial: Solve 10 equations as fast as you can - Long Run: Solve as many equations as you can before time runs out - Head-to-Head: Compete with your friends in real time on the same device via split-screen Ranks 1. Jock (lowest) 2. Tally-Marking Monkey 3, Sudoku Fan 4, Bean Counter 5, Nerd 6, Uber Nerd 7, Doctor (highest) Sharing Players can share scores and ranks via Facebook Connect Ages This app is suitable for kids who want to improve math skills or just have fun, from 7 to 99 years old!

SPB Brain Evolution: intellect

SPB Brain Evolution is an intellectual game that helps to train the brain and improve memory, logic,

SPB Brain Evolution is an intellectual game that helps to train the brain and improve memory, logic, arithmetic, and puzzle-solving skills using your touchscreen mobile phone. The application is a suit of 12 games, which have to be played in sequence: only good results in a game unlock the next one. Watch this video to sneak a peek on how the game is organized and what benefits it offers to the mobile users. spb.com

C++ Programming Tutorial - Par

After a long hiatus, I decided to make a new C++ Tutorial. So, HERE IT IS! :D

After a long hiatus, I decided to make a new C++ Tutorial. So, HERE IT IS! :D

Area, Perimeter, and Diagonal

demonstrations.wolfram.com The Wolfram Demonstrations Project contains thousands of free interactive

demonstrations.wolfram.com The Wolfram Demonstrations Project contains thousands of free interactive visualizations, with new entries added daily. Using the uncertain calculus [1] and interval arithmetic, simple analytical solutions are derived and used to calculate the area, perimeter, and diagonal of a rectangle with the bottom left corner at the origin and the top right corner (x, y) defined by... Contributed by: Valter Yoshihiko Aibe and Mikhail Dimitrov Mikhailov

CS Podcast Group 23 - When to

Podcast for Computer Systems. When to use unsigned arithmetic. By Nikolai Belkin and William Luu.

Podcast for Computer Systems. When to use unsigned arithmetic. By Nikolai Belkin and William Luu.

Introducing: The Mischief Mach

The supervillain from the Super Solver series of educational games, reimagined as a killing machine.

The supervillain from the Super Solver series of educational games, reimagined as a killing machine. Why settle for an incompetent robot army when you can BE a one-man robot army!? He already took over my computer and is probably spreading across the Internet as we speak, so get your reading and arithmetic skills ready... Created by Sam Lloyd as a final project for Computer Science 22: Digital Modeling at Dartmouth College. With a tussive cameo by Amanda Tsao! Soundtrack: In The Hall Of The Mountain King (Techno Remix) by DJ Liquid. The Super Solver series and all characters and representations therein are property of The Learning Company.

Arithmetic Game - Project in H

Arithmetic Game - Project in HUMAN-COMPUTER INTERACTION Class (2nd Years) 2008 JAVA Base

Arithmetic Game - Project in HUMAN-COMPUTER INTERACTION Class (2nd Years) 2008 JAVA Base

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